select count(id) as 'count' FROM `doctor` where 1 and display='1'
AND(
chinese_name like '%®ion=%'
OR english_name like '%®ion=%'
)
and ( category = '≥nder=' ) and ( price >= and price <= ) ORDER BY `grade`, `grade_2`, `english_name` ASC, `doctor_id`
Publie Holiday doctor list, christmas holiday doctor